Tool/everything-claude-code/docs/zh-CN/skills/regex-vs-llm-structured-text/SKILL.md
选择在解析结构化文本时使用正则表达式还是大型语言模型的决策框架——从正则表达式开始,仅在低置信度的边缘情况下添加大型语言模型。
npx skillsauth add lyxjack/toolbox regex-vs-llm-structured-textInstall this skill globally with one command. Works with Claude Code, Cursor, and Windsurf.
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一个用于解析结构化文本(测验、表单、发票、文档)的实用决策框架。核心见解是:正则表达式能以低成本、确定性的方式处理 95-98% 的情况。将昂贵的 LLM 调用留给剩余的边缘情况。
Is the text format consistent and repeating?
├── Yes (>90% follows a pattern) → Start with Regex
│ ├── Regex handles 95%+ → Done, no LLM needed
│ └── Regex handles <95% → Add LLM for edge cases only
└── No (free-form, highly variable) → Use LLM directly
Source Text
│
▼
[Regex Parser] ─── Extracts structure (95-98% accuracy)
│
▼
[Text Cleaner] ─── Removes noise (markers, page numbers, artifacts)
│
▼
[Confidence Scorer] ─── Flags low-confidence extractions
│
├── High confidence (≥0.95) → Direct output
│
└── Low confidence (<0.95) → [LLM Validator] → Output
import re
from dataclasses import dataclass
@dataclass(frozen=True)
class ParsedItem:
id: str
text: str
choices: tuple[str, ...]
answer: str
confidence: float = 1.0
def parse_structured_text(content: str) -> list[ParsedItem]:
"""Parse structured text using regex patterns."""
pattern = re.compile(
r"(?P<id>\d+)\.\s*(?P<text>.+?)\n"
r"(?P<choices>(?:[A-D]\..+?\n)+)"
r"Answer:\s*(?P<answer>[A-D])",
re.MULTILINE | re.DOTALL,
)
items = []
for match in pattern.finditer(content):
choices = tuple(
c.strip() for c in re.findall(r"[A-D]\.\s*(.+)", match.group("choices"))
)
items.append(ParsedItem(
id=match.group("id"),
text=match.group("text").strip(),
choices=choices,
answer=match.group("answer"),
))
return items
标记可能需要 LLM 审核的项:
@dataclass(frozen=True)
class ConfidenceFlag:
item_id: str
score: float
reasons: tuple[str, ...]
def score_confidence(item: ParsedItem) -> ConfidenceFlag:
"""Score extraction confidence and flag issues."""
reasons = []
score = 1.0
if len(item.choices) < 3:
reasons.append("few_choices")
score -= 0.3
if not item.answer:
reasons.append("missing_answer")
score -= 0.5
if len(item.text) < 10:
reasons.append("short_text")
score -= 0.2
return ConfidenceFlag(
item_id=item.id,
score=max(0.0, score),
reasons=tuple(reasons),
)
def identify_low_confidence(
items: list[ParsedItem],
threshold: float = 0.95,
) -> list[ConfidenceFlag]:
"""Return items below confidence threshold."""
flags = [score_confidence(item) for item in items]
return [f for f in flags if f.score < threshold]
def validate_with_llm(
item: ParsedItem,
original_text: str,
client,
) -> ParsedItem:
"""Use LLM to fix low-confidence extractions."""
response = client.messages.create(
model="claude-haiku-4-5-20251001", # Cheapest model for validation
max_tokens=500,
messages=[{
"role": "user",
"content": (
f"Extract the question, choices, and answer from this text.\n\n"
f"Text: {original_text}\n\n"
f"Current extraction: {item}\n\n"
f"Return corrected JSON if needed, or 'CORRECT' if accurate."
),
}],
)
# Parse LLM response and return corrected item...
return corrected_item
def process_document(
content: str,
*,
llm_client=None,
confidence_threshold: float = 0.95,
) -> list[ParsedItem]:
"""Full pipeline: regex -> confidence check -> LLM for edge cases."""
# Step 1: Regex extraction (handles 95-98%)
items = parse_structured_text(content)
# Step 2: Confidence scoring
low_confidence = identify_low_confidence(items, confidence_threshold)
if not low_confidence or llm_client is None:
return items
# Step 3: LLM validation (only for flagged items)
low_conf_ids = {f.item_id for f in low_confidence}
result = []
for item in items:
if item.id in low_conf_ids:
result.append(validate_with_llm(item, content, llm_client))
else:
result.append(item)
return result
来自一个生产中的测验解析管道(410 个项目):
| 指标 | 值 | |--------|-------| | 正则表达式成功率 | 98.0% | | 低置信度项目 | 8 (2.0%) | | 所需 LLM 调用次数 | ~5 | | 相比全 LLM 的成本节省 | ~95% | | 测试覆盖率 | 93% |
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